Predict the output of below program:
#include <stdio.h>
int main()
{
printf("%c ", "GeeksQuiz"[5]);
return 0;
}
|
(A) Compile-time error
(B) Runtime error
(C) Q
(D) s
Answer: (C)
Explanation: The crux of the program lies in the expression: “GeeksQuiz”[5].
This expression is broken down by the compiler as: *(“GeeksQuiz” + 5). Adding 5 to the base address of the string increments the pointer(lets say a pointer was pointing to the start(G) of the string initially) to point to Q. Applying value-of operator gives the character at the location pointed to by the pointer i.e. Q.
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Last Updated :
11 Jan, 2013
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