C++ | Inheritance | Question 8

C

#include<iostream>
using namespace std;

class Base
{
public:
    int fun()  { cout << \"Base::fun() called\"; }
    int fun(int i)  { cout << \"Base::fun(int i) called\"; }
};

class Derived: public Base
{
public:
    int fun() {  cout << \"Derived::fun() called\"; }
};

int main()
{
    Derived d;
    d.fun(5);
    return 0;
}

(A)

Base::fun(int i) called

(B)

Derived::fun() called

(C)

Base::fun() called

(D)

Compiler Error

Answer: (D)
Explanation:

If a derived class writes its own method, then all functions of base class with same name become hidden, even if signatures of base class functions are different. In the above question, when fun() is rewritten in Derived, it hides both fun() and fun(int) of base class.

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