C++ | Inheritance | Question 7

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#include<iostream>
using namespace std;
  
class Base
{
public:
    void show()
    {
        cout<<" In Base ";
    }
};
  
class Derived: public Base
{
public:
    int x;
    void show()
    {
        cout<<"In Derived ";
    }
    Derived()
    {
        x = 10;
    }
};
  
int main(void)
{
    Base *bp, b;
    Derived d;
    bp = &d;
    bp->show();
    cout << bp->x;    
    return 0;
}

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(A) Compiler Error in line ” bp->show()”
(B) Compiler Error in line ” cout <x”
(C) In Base 10
(D) In Derived 10


Answer: (B)

Explanation: A base class pointer can point to a derived class object, but we can only access base class member or virtual functions using the base class pointer because object slicing happens when a derived class object is assigned to a base class object. Additional attributes of a derived class object are sliced off to form the base class object.


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Improved By : Pallabi Mondal

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