C++ | Inheritance | Question 7

#include<iostream>
using namespace std;
  
class Base
{
public:
    void show()
    {
        cout<<" In Base ";
    }
};
  
class Derived: public Base
{
public:
    int x;
    void show()
    {
        cout<<"In Derived ";
    }
    Derived()
    {
        x = 10;
    }
};
  
int main(void)
{
    Base *bp, b;
    Derived d;
    bp = &d;
    bp->show();
    cout << bp->x;    
    return 0;
}

(A) Compiler Error in line ” bp->show()”
(B) Compiler Error in line ” cout <x”
(C) In Base 10
(D) In Derived 10


Answer: (B)

Explanation: A base class pointer can point to a derived class object, but we can only access base class member or virtual functions using the base class pointer.


Quiz of this Question



My Personal Notes arrow_drop_up

Article Tags :
Practice Tags :



Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.