Related Articles

Related Articles

C++ | Inheritance | Question 14
  • Difficulty Level : Easy
  • Last Updated : 23 Sep, 2014

Consider the below C++ program.

filter_none

edit
close

play_arrow

link
brightness_4
code

#include<iostream>
using namespace std;
class A
{
public:
     A(){ cout <<"1";}
     A(const A &obj){ cout <<"2";}
};
  
class B: virtual A
{
public:
    B(){cout <<"3";}
    B(const B & obj){cout<<"4";}
};
  
class C: virtual A
{
public:
   C(){cout<<"5";}
   C(const C & obj){cout <<"6";}
};
  
class D:B,C
{
public:
    D(){cout<<"7";}
    D(const D & obj){cout <<"8";}
};
  
int main()
{
   D d1;
   D d(d1);
}

chevron_right


Which of the below is not printed?

This question is contributed by Sudheendra Baliga
(A) 2
(B) 4
(C) 6
(D) All of the above


Answer: (D)

Explanation: Output will be 13571358 as 1357 (for D d1) and as 1358 (for D d(d1))……reason is that ……during inheritance we need to explicitly call copy constructor of base class otherwise only default constructor of base class is called. One more thing, as we are using virtual before base class, there will be only one copy of base class in multiple inheritance. And without virtual output will be……13157….&…13158 as (1315713158) respectively for each derived class object.

Quiz of this Question

Attention reader! Don’t stop learning now. Get hold of all the important C++ Foundation and STL concepts with the C++ Foundation and STL courses at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up
Recommended Articles
Page :