C# | Get an enumerator that iterates through the SortedSet
Last Updated :
01 Feb, 2019
SortedSet<T>.GetEnumerator Method is used to return an enumerator that iterates through the SortedSet<T>.
Syntax:
public System.Collections.Generic.SortedSet<T>.Enumerator GetEnumerator ();
Return Value: This method returns an enumerator that iterates through the SortedSet<T> in sorted order.
Below programs illustrate the use of the above-discussed method:
Example 1:
using System;
using System.Collections.Generic;
class GFG {
public static void Main()
{
SortedSet< int > mySortedSet = new SortedSet< int >();
mySortedSet.Add(2);
mySortedSet.Add(4);
mySortedSet.Add(6);
mySortedSet.Add(8);
mySortedSet.Add(10);
SortedSet< int >.Enumerator em = mySortedSet.GetEnumerator();
display(em);
}
static void display(IEnumerator< int > em)
{
while (em.MoveNext()) {
int val = em.Current;
Console.WriteLine(val);
}
}
}
|
Output:
2
4
6
8
10
Example 2:
using System;
using System.Collections.Generic;
class GFG {
public static void Main()
{
SortedSet< string > mySortedSet = new SortedSet< string >();
mySortedSet.Add( "C#" );
mySortedSet.Add( "PHP" );
mySortedSet.Add( "HTML" );
mySortedSet.Add( "Java" );
mySortedSet.Add( "C++" );
SortedSet< string >.Enumerator em = mySortedSet.GetEnumerator();
display(em);
}
static void display(IEnumerator< string > em)
{
while (em.MoveNext()) {
string val = em.Current;
Console.WriteLine(val);
}
}
}
|
Output:
C#
C++
HTML
Java
PHP
Note:
- The foreach statement of the C# language hides the complexity of the enumerators. Therefore, using foreach is recommended, instead of directly manipulating the enumerator.
- Enumerators can be used to read the data in the collection, but they cannot be used to modify the underlying collection.
- Current returns the same object until either MoveNext or Reset is called. MoveNext sets Current to the next element.
- An enumerator remains valid as long as the collection remains unchanged. If changes are made to the collection, such as adding, modifying, or deleting elements, the enumerator is irrecoverably invalidated and its behavior is undefined.
- This method is an O(log n) operation.
Reference:
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