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C++ | Function Overloading and Default Arguments | Question 5

  • Last Updated : 28 Jun, 2021

Output of following program?

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#include <iostream>
using namespace std;
  
int fun(int=0, int = 0);
  
int main()
{
  cout << fun(5);
  return 0;
}
  
int fun(int x, int y) { return (x+y); }

(A) Compiler Error
(B) 5
(C) 0
(D) 10


Answer: (B)

Explanation: The statement “int fun(int=0, int=0)” is declaration of a function that takes two arguments with default values as 0 and 0.

The last statement is definition of fun().

When we make a call fun(5), x gets the value 5 and y gets 0. So the returned value is 5.

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