C++ | friend keyword | Question 2
Predict the output the of following program.
#include <iostream>using namespace std; class B;class A { int a;public: A():a(0) { } void show(A& x, B& y);}; class B {private: int b;public: B():b(0) { } friend void A::show(A& x, B& y);}; void A::show(A& x, B& y) { x.a = 10; cout << "A::a=" << x.a << " B::b=" << y.b;} int main() { A a; B b; a.show(a,b); return 0;} |
(A) Compiler Error
(B) A::a=10 B::b=0
(C) A::a=0 B::b=0
Answer: (B)
Explanation: This is simple program where a function of class A is declared as friend of class B.
Since show() is friend, it can access private data members of B.
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