C++ | Destructors | Question 2

Predict the output of following C++ program

#include <iostream>
using namespace std;

int i;

class A
{
public:
    ~A()
    {
        i=10;
    }
};

int foo()
{
    i=3;
    A ob;
    return i;
}

int main()
{
    cout << foo() << endl;
    return 0;
}

(A) 0
(B) 3
(C) 10
(D) None of the above


Answer: (B)

Explanation: While returning from a function, destructor is the last method to be executed. The destructor for the object “ob” is called after the value of i is copied to the return value of the function. So, before destructor could change the value of i to 10, the current value of i gets copied & hence the output is i = 3. See this for more details.

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