C++ | Constructors | Question 17

Output?

filter_none

edit
close

play_arrow

link
brightness_4
code

#include<iostream>
#include<string.h>
using namespace std;
  
class String
{
    char *str;
public:
     String(const char *s);
     void change(int index, char c) { str[index] = c; }
     char *get() { return str; }
};
  
String::String(const char *s)
{
    int l = strlen(s);
    str = new char[l+1];
    strcpy(str, s);
}
  
int main()
{
   String s1("geeksQuiz");
   String s2 = s1;
   s1.change(0, 'G');
   cout << s1.get() << " ";
   cout << s2.get();
}

chevron_right


(A) GeeksQuiz
geeksQuiz
(B) GeeksQuiz
GeeksQuiz
(C) geeksQuiz
geeksQuiz
(D) geeksQuiz
GeeksQuiz


Answer: (B)

Explanation: Since there is no copy constructor, the compiler creates a copy constructor. The compiler created copy constructor does shallow copy in line ” String s2 = s1;”

So str pointers of both s1 and s2 point to the same location.

There must be a user defined copy constructor in classes with pointers ot dynamic memory allocation.

Quiz of this Question

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up
Article Tags :
Practice Tags :


Be the First to upvote.


Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.