Skip to content
Related Articles

Related Articles

C | Arrays | Question 7
  • Difficulty Level : Easy
  • Last Updated : 03 Aug, 2018

Consider the following declaration of a ‘two-dimensional array in C:




char a[100][100]; 

Assuming that the main memory is byte-addressable and that the array is stored starting from memory address 0, the address of a[40][50] is (GATE CS 2002)

(A) 4040
(B) 4050
(C) 5040
(D) 5050


Answer: (B)

Explanation:

Address of a[40][50] = Base address + 40*100*element_size + 50*element_size
                      = 0 + 4000*1 + 50*1
                     = 4050
Based on row major or column major
if row major then the result will be 4050
if column major then 
            Address of a[40][50] = Base address + 50*100*element_size + 40*element_size
                      = 0 + 5000*1 + 40*1
                     = 5040


Quiz of this Question

Want to learn from the best curated videos and practice problems, check out the C Foundation Course for Basic to Advanced C.
My Personal Notes arrow_drop_up
Recommended Articles
Page :