Predict the output of below program:
#include <stdio.h> int main()
{ int arr[5];
// Assume base address of arr is 2000 and size of integer is 32 bit
printf("%u %u", arr + 1, &arr + 1);
return 0;
} |
(A) 2004 2020
(B) 2004 2004
(C) 2004 Garbage value
(D) The program fails to compile because Address-of operator cannot be used with array name
Answer: (A)
Explanation: Name of array in C gives the address(except in sizeof operator) of the first element. Adding 1 to this address gives the address plus the sizeof type the array has. Applying the Address-of operator before the array name gives the address of the whole array. Adding 1 to this address gives the address plus the sizeof whole array.