Assume that the size of int is 4.
#include <stdio.h> void f( char **);
int main()
{ char *argv[] = { "ab" , "cd" , "ef" , "gh" , "ij" , "kl" };
f(argv);
return 0;
} void f( char **p)
{ char *t;
t = (p += sizeof ( int ))[-1];
printf ( "%s\n" , t);
} |
(A) ab
(B) cd
(C) ef
(D) gh
Answer: (D)
Explanation: The expression (p += sizeof(int))[-1] can be written as (p += 4)[-1] which can be written as (p = p+4)[-] which returns address p+3 which is address of fourth element in argv[].
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