Assume that the size of int is 4.
#include <stdio.h>
void f(char**);
int main()
{
char *argv[] = { "ab", "cd", "ef", "gh", "ij", "kl" };
f(argv);
return 0;
}
void f(char **p)
{
char *t;
t = (p += sizeof(int))[-1];
printf("%s\n", t);
}
|
(A) ab
(B) cd
(C) ef
(D) gh
Answer: (D)
Explanation: The expression (p += sizeof(int))[-1] can be written as (p += 4)[-1] which can be written as (p = p+4)[-] which returns address p+3 which is address of fourth element in argv[].
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Last Updated :
28 Jun, 2021
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