C | Advanced Pointer | Question 4
#include <stdio.h> char *c[] = {"GeksQuiz", "MCQ", "TEST", "QUIZ"};char **cp[] = {c+3, c+2, c+1, c};char ***cpp = cp; int main(){ printf("%s ", **++cpp); printf("%s ", *--*++cpp+3); printf("%s ", *cpp[-2]+3); printf("%s ", cpp[-1][-1]+1); return 0;} |
(A) TEST sQuiz Z CQ
(B) MCQ Quiz Z CQ
(C) TEST Quiz Z CQ
(D) GarbageValue sQuiz Z CQ
Answer: (A)
Explanation: Let us first consider **++cpp. Precedence of prefix increment and de-reference is same and associativity of both of them is right to left. So the expression is evaluated as **(++cpp). So cpp points to c+2. So we get “TEST” as output. Note the de-reference operator twice.
Similarly, you may try other expressions yourself with the help of precedence table.
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