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C | Advanced Pointer | Question 4

  • Difficulty Level : Easy
  • Last Updated : 28 Jun, 2021

Take a step-up from those "Hello World" programs. Learn to implement data structures like Heap, Stacks, Linked List and many more! Check out our Data Structures in C course to start learning today.

#include <stdio.h>
char *c[] = {"GeksQuiz", "MCQ", "TEST", "QUIZ"};
char **cp[] = {c+3, c+2, c+1, c};
char ***cpp = cp;
int main()
    printf("%s ", **++cpp);
    printf("%s ", *--*++cpp+3);
    printf("%s ", *cpp[-2]+3);
    printf("%s ", cpp[-1][-1]+1);
    return 0;

(A) TEST sQuiz Z CQ
(B) MCQ Quiz Z CQ
(C) TEST Quiz Z CQ
(D) GarbageValue sQuiz Z CQ

Answer: (A)

Explanation: Let us first consider **++cpp. Precedence of prefix increment and de-reference is same and associativity of both of them is right to left. So the expression is evaluated as **(++cpp). So cpp points to c+2. So we get “TEST” as output. Note the de-reference operator twice.

Similarly, you may try other expressions yourself with the help of precedence table.

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