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bits.Sub() Function in Golang with Examples

  • Last Updated : 28 Apr, 2020

The bits.Sub() Function in Golang is used to find the difference of a, b and borrow, i.e. diff = a – b – borrow. Here the borrow must be 0 or 1; otherwise, the behavior is undefined. To access this function, one needs to imports the math/bits package in the program. The return value of the borrowOutput will be always 0 or 1 in any case.

Syntax:

func Sub(a, b, borrow uint) (diff, borrowOut uint)

Parameters: This function takes three parameters of uint type, i.e., a, b, and borrow. The value of borrow parameter is either 1 or 0

Return Value: This function return two values of uint type, i.e., diff and borrowOut. Here diff contains the result of a – b – borrow and borrowOut is either 1 or 0.

Example 1:






// Golang program to illustrate bits.Sub() Function 
package main 
    
import ( 
    "fmt"
    "math/bits"
    
// Main function 
func main() { 
    
    // Finding diff and borrowOu 
    // of the specified numbers 
    // Using Sub() function 
    nvalue_1, borrowOut := bits.Sub(4, 3, 0) 
    fmt.Println("Diff:", nvalue_1) 
    fmt.Println("BorrowOut :", borrowOut ) 
    

Output:

Diff: 1
BorrowOut : 0

Example 2:




// Golang program to illustrate bits.Sub() Function
package main
  
import (
    "fmt"
    "math/bits"
)
  
// Main function
func main() {
  
    // Finding diff and borrowOut
    // of the specified numbers
    // Using Sub() function
  
    var a, b, borrow uint = 10, 5, 1
    Diff, borrowOut := bits.Sub(a, b, borrow)
    fmt.Println("Number 1:", a)
    fmt.Println("Number 2:", b)
    fmt.Println("Borrow :", borrow)
    fmt.Println("Diff:", Diff)
    fmt.Println("BorrowOut :", borrowOut)
  
}

Output:

Number 1: 10
Number 2: 5
Borrow : 1
Diff: 4
BorrowOut : 0



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