BIT_OR() Function in MySQL

BIT_OR() function in MySQL is used to return the bitwise OR of all bits in a given expression. It first converts all decimal values into binary values, and then perform bitwise or operation on those binary values.

Syntax :

BIT_OR(expr)

Parameter : This method accepts only one parameter.

• expr –
  Input expression on which we want to apply BIT_OR function.

Returns : It returns bitwise OR of all bits in a given expression.

Example-1 :
To demonstrate the working of the BIT_OR function, we will have to first create a table named EmployeeDetails.

CREATE TABLE EmployeeDetails(
Employee_Id INT AUTO_INCREMENT,  
Employee_Name VARCHAR(100) NOT NULL,
Working_At VARCHAR(20) NOT NULL,
Work_Location  VARCHAR(20) NOT NULL,
Joining_Date DATE NOT NULL,
Annual_Income INT  NOT NULL,
PRIMARY KEY(Employee_Id )
);

Now, inserting the values into the table –

INSERT INTO EmployeeDetails (Employee_Name, Working_At, 
Work_Location, Joining_Date, Annual_Income)
VALUES
('Amit Khan', 'XYZ Digital', 'Kolkata', '2019-10-06', 350000),
('Shreetama Pal', 'ABC Corp.', 'Kolkata', '2018-12-16', 500000),
('Aniket Sharma', 'PQR Soln.', 'Delhi', '2020-01-11', 300000),
('Maitree Jana', 'XYZ Digital', 'Kolkata', '2019-05-01', 400000),
('Priyanka Ojha', 'ABC Corp.', 'Delhi', '2019-02-13', 350000),
('Sayani Mitra', 'XYZ Digital', 'Kolkata', '2019-09-15', 320000),
('Nitin Dey', 'PQR Soln.', 'Delhi', '2019-10-06', 250000),
('Sujata Samanta', 'PQR Soln.', 'Kolkata', '2020-10-06', 350000),
('Sudip Majhi', 'ABC Corp.', 'Delhi', '2018-10-30', 600000),
('Sanjoy Kohli', 'XYZ Digital', 'Delhi', '2019-04-18', 450000);

To verify used the following command as follows –

Select * FROM EmployeeDetails;

Output :

EMPLOYEE_ID	EMPLOYEE_NAME	WORKING_AT	WORK_LOCATION	JOINING_DATE	ANNUAL_INCOME
1	Amit Khan	XYZ Digital	Kolkata	2019-10-06	350000
2	Shreetama Pal	ABC Corp.	Kolkata	2018-12-16	500000
3	Aniket Sharma	PQR Soln.	Delhi	2020-01-11	300000
4	Maitree Jana	XYZ Digital	Kolkata	2019-05-01	400000
5	Priyanka Ojha	ABC Corp.	Delhi	2019-02-13	350000
6	Sayani Mitra	XYZ Digital	Kolkata	2019-09-15	320000
7	Nitin Dey	PQR Soln.	Delhi	2019-10-06	250000
8	Sujata Samanta	PQR Soln.	Kolkata	2020-10-06	350000
9	Sudip Majhi	ABC Corp.	Delhi	2018-10-30	600000
10	Sanjoy Kohli	XYZ Digital	Delhi	2019-04-18	450000

Now we will find the BIT_OR of the annual income of all the employees company-wise from the EmployeeDetails table.

SELECT Working_At, BIT_OR(Annual_Income) AS BITORINCOME 
FROM EmployeeDetails group by Working_At;

Output :

WORKING_AT	BITORINCOME
XYZ Digital	524272
ABC Corp.	1046512
PQR Soln.	514032

Example-2 :
Now we will find the BIT_OR of the annual income of all the employee location wise from the EmployeeDetails table.

SELECT Work_Location, BIT_OR(Annual_Income) AS BITORINCOME 
FROM EmployeeDetails 
Group By Work_Location;

Output :

WORK_LOCATION	BITORINCOME
Kolkata	524208
Delhi	1048560

Example-3 :
Firstly Creating a StudentMarks table –

CREATE TABLE StudentMarks(
StudentId INT AUTO_INCREMENT,  
StudentName VARCHAR(100) NOT NULL,
Class VARCHAR(20) NOT NULL,
Roll INT NOT NULL,
Sub1Mark INT NOT NULL,
Sub2Mark INT NOT NULL,
Sub3Mark INT NOT NULL,
TotalMarks INT NOT NULL,
PRIMARY KEY(StudentId)
);

Inserting data into the table –

INSERT INTO StudentMarks
(StudentName, Class, Roll, Sub1Mark, 
Sub2Mark, Sub3Mark, TotalMarks)
VALUES
('Amit Jana', 'V', 10100, 85, 80, 95, 260),
('Labanya Mallick', 'VI', 11000, 81, 89, 95, 265),
('Virat Sharma', 'VI', 12000, 75, 83, 90, 248),
('Sayani Samanta', 'V', 13000, 95, 90, 99, 284),
('Riyanka Panda', 'V', 14000, 70, 87, 88, 245),  
('Ritika Shah', 'VI', 15000, 78, 89, 90, 257);

To verify used the following command as follows –

SELECT  * From StudentMarks;

Output :

STUDENTID	STUDENTNAME	CLASS	ROLL	SUB1MARK	SUB2MARK	SUB3MARK	TOTALMARKS
1	Amit Jana	V	10100	85	80	95	260
2	Labanya Mallick	VI	11000	81	89	95	265
3	Virat Sharma	VI	12000	75	83	90	248
4	Sayani Samanta	V	13000	95	90	99	284
5	Riyanka Panda	V	14000	70	87	88	245
6	Ritika Shah	VI	15000	78	89	90	257

Now we will find the BIT_OR of total marks of all the student class wise from the StudentMarks table.

SELECT Class, BIT_OR(TotalMarks) AS BITORMARKS 
FROM StudentMarks 
Group By Class;

Output :

CLASS	BITORMARKS
V	509
VI	505