BIT_AND() function in MySQL

BIT_AND() :

This function in MySQL is used to return the Bitwise AND of all bits in a given expression. It first converts all decimal values into binary values, and then perform bitwise and operation on those binary values.

The BIT_AND() function works by performing a bitwise AND operation on each pair of corresponding bits in the binary representation of the numbers. The result is a new binary number with a 1 in each position.

Note: that BIT_AND() can be used with any integer data type, including BIGINT, INT, MEDIUMINT, SMALLINT, and TINYINT.

Syntax :

BIT_AND(expr)

Parameter : 

This method accepts only one parameter.

• expr – Input expression on which we want to apply BIT_AND function.

Returns :

It returns bitwise AND of all bits in a given expression.

Example-1 :

Working of the BIT_AND function in the columns of table

Creating an Employee Table – 

CREATE TABLE EmployeeDetails(

Employee_Id INT AUTO_INCREMENT,  
Employee_Name VARCHAR(100) NOT NULL,
Working_At VARCHAR(20) NOT NULL,
Work_Location  VARCHAR(20) NOT NULL,
Joining_Date DATE NOT NULL,
Annual_Income INT  NOT NULL,
PRIMARY KEY(Employee_Id )
);

Inserting the values into the table – 

INSERT INTO  
EmployeeDetails(Employee_Name , Working_At, Work_Location, Joining_Date, Annual_Income )

VALUES
('Amit Khan' , 'XYZ Digital' , 'Kolkata' ,'2019-10-06' , 350000 ) ,
('Shreetama Pal' , 'ABC Corp.' , 'Kolkata' ,'2018-12-16' , 500000 )  ,
('Aniket Sharma' , 'PQR Soln.' , 'Delhi' , '2020-01-11' ,300000 ) ,
('Maitree Jana' , 'XYZ Digital' , 'Kolkata' ,'2019-05-01' , 400000 ) ,
('Priyanka Ojha' , 'ABC Corp.' , 'Delhi' ,'2019-02-13' , 350000 ) ,
('Sayani Mitra' , 'XYZ Digital' , 'Kolkata' ,'2019-09-15' , 320000 ) ,
('Nitin Dey' , 'PQR Soln.' , 'Delhi' ,'2019-10-06' , 250000 ) ,
('Sujata Samanta' , 'PQR Soln.' , 'Kolkata' ,'2020-10-06' , 350000 ) ,
('Sudip Majhi' , 'ABC Corp.' , 'Delhi' ,'2018-10-30' , 600000 ) ,
('Sanjoy Kohli' , 'XYZ Digital' ,'Delhi' ,'2019-04-18' , 450000 ) ;

The table will look as follows.

Select * FROM EmployeeDetails;

Output :

EMPLOYEE_ID	EMPLOYEE_NAME	WORKING_AT	WORK_LOCATION	JOINING_DATE	ANNUAL_INCOME
1	Amit Khan	XYZ Digital	Kolkata	2019-10-06	350000
2	Shreetama Pal	ABC Corp.	Kolkata	2018-12-16	500000
3	Aniket Sharma	PQR Soln.	Delhi	2020-01-11	300000
4	Maitree Jana	XYZ Digital	Kolkata	2019-05-01	400000
5	Priyanka Ojha	ABC Corp.	Delhi	2019-02-13	350000
6	Sayani Mitra	XYZ Digital	Kolkata	2019-09-15	320000
7	Nitin Dey	PQR Soln.	Delhi	2019-10-06	250000
8	Sujata Samanta	PQR Soln.	Kolkata	2020-10-06	350000
9	Sudip Majhi	ABC Corp.	Delhi	2018-10-30	600000
10	Sanjoy Kohli	XYZ Digital	Delhi	2019-04-18	450000

Now we will find the BIT_AND of annual income of all the employees company-wise from the “EmployeeDetails” table. 

SELECT Working_At, BIT_AND(Annual_Income) AS BITANDINCOME
FROM employeedetails group by Working_At;

Output :

WORKING_AT	BITANDINCOME
XYZ Digital	262144
ABC Corp.	65792
PQR Soln.	4096

Example-2 :

Now we will find the BIT_AND of annual income of all the employee location wise from the “EmployeeDetails” table. 

SELECT Work_Location, BIT_AND(Annual_Income) AS BITANDINCOME
FROM EmployeeDetails group by  Work_Location;

Output :

WORK_LOCATION	BITANDINCOME
Kolkata	262144
Delhi	0

Example-3 :

Creating a Student table –

CREATE TABLE StudentMarks
(
StudentId INT AUTO_INCREMENT,  
StudentName VARCHAR(100) NOT NULL,
Class VARCHAR(20) NOT NULL,
Roll INT NOT NULL,
Sub1Mark INT NOT NULL,
Sub2Mark INT NOT NULL,
Sub3Mark INT NOT NULL,
TotalMarks INT NOT NULL,
PRIMARY KEY(StudentId )
);

Inserting data into the Table –

INSERT INTO StudentMarks
(StudentName, Class, Roll, Sub1Mark, Sub2Mark, Sub3Mark, TotalMarks)
VALUES
('Amit Jana', 'V', 10100, 85, 80, 95, 260),
('Labanya Mallick', 'VI', 11000, 81, 89, 95, 265),
('Virat Sharma', 'VI', 12000, 75, 83, 90, 248),
('Sayani Samanta', 'V', 13000, 95, 90, 99, 284),
('Riyanka Panda', 'V', 14000, 70, 87, 88, 245),  
('Ritika Shah', 'VI', 15000, 78, 89, 90, 257);

The table will look as follows.

SELECT  * from StudentMarks;

Output :

STUDENTID	STUDENTNAME	CLASS	ROLL	SUB1MARK	SUB2MARK	SUB3MARK	TOTALMARKS
1	Amit Jana	V	10100	85	80	95	260
2	Labanya Mallick	VI	11000	81	89	95	265
3	Virat Sharma	VI	12000	75	83	90	248
4	Sayani Samanta	V	13000	95	90	99	284
5	Riyanka Panda	V	14000	70	87	88	245
6	Ritika Shah	VI	15000	78	89	90	257

Now we will find the BIT_AND of total marks of all the student class wise from the “StudentMarks” table.

SELECT Class, BIT_AND(TotalMarks) AS BITANDMARKS
FROM StudentMarks group by Class;

Output :

CLASS	BITANDMARKS
V	4
VI	0