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Bit manipulation | Swap Endianness of a number
• Last Updated : 09 Sep, 2019

Little Endian and Big Endian are ways or storing data in machines. Some machines might use Little Endian byte ordering while others might use big Endian. This creates an inconsistency when you are transferring data from a Big Endian machine to a Little Endian machine. Usually, the compiler takes care of the conversion. But, in networking, Big Endian is used as the standard for the exchange of data between networks. Therefore, Little Endian machines need to convert their data to Big Endian while sending data through a network. Similarly, Little Endian machines need to swap the byte ordering when they receive data from a network.

So Endianness comes into picture when you are sending and receiving data across the network from one host to another host. If the sender and receiver computer have different Endianness, then there is a need to swap the Endianness so that it is compatible.

Therefore, it is important to convert the data to little Endian or big Endian so that there is consistency and data integrity. In this article, we will look at how the Endianness of a number can be swapped. This is also a common interview question.

## Approach :

1. Get the rightmost 8 bits of the number by anding it with 0x000000FF since the last 8 bits are all ones and the rest are all zeros, the result will be rightmost 8 bits of the number. The result is stored in a variable called leftmost_byte
2. Similarly, get the next 8 bits (from the right, right middle) of the number by anding it with 0x0000FF00. The result is stored in left_middle_byte
3. Obtain the next 8 bits of the number by anding it with 0x00FF0000. The result is stored in right_middle_byte
4. Finally, get the leftmost 8 bits of the number by anding it with 0xFF000000. The result is stored in rightmost_byte
5. Now that we have all the 4 bytes of the number, we need to concatenate it in reverse order. i.e, swap the Endianness of the number. To do this, we shift the rightmost 8 bits by 24 to the left so that it becomes the leftmost 8 bits. We left shift the right middle byte by 16 (to store it as the left middle byte) We left shift the left middle byte by 8 (to store it as the right muddle byte) We finally left shift the leftmost byte by 24 to the left
6. Now, we logically “or” (concatenate) all the variables to obtain the result.

Consider the number 0x12345678. The number is 4 bytes wide. In Big Endian, this number is represented as: In Little Endian, the same number is represented as: Examples:

Input : 0x12345678
Output : 0x78563412

Input : 0x87654321
Output : 0x21436587

Implementation:

## C++

 `// C++ program to print the difference ``// of Alternate Nodes ``#include  ``using` `namespace` `std;`` ` `// Function to swap a value from ``// big Endian to little Endian and ``// vice versa. ``int` `swap_Endians(``int` `value) ``{ `` ` `    ``// This var holds the leftmost 8 ``    ``// bits of the output. ``    ``int` `leftmost_byte; `` ` `    ``// This holds the left middle ``    ``// 8 bits of the output ``    ``int` `left_middle_byle; `` ` `    ``// This holds the right middle ``    ``// 8 bits of the output ``    ``int` `right_middle_byte; `` ` `    ``// This holds the rightmost ``    ``// 8 bits of the output ``    ``int` `rightmost_byte; `` ` `    ``// To store the result ``    ``// after conversion ``    ``int` `result; `` ` `    ``// Get the rightmost 8 bits of the number ``    ``// by anding it 0x000000FF. since the last ``    ``// 8 bits are all ones, the result will be the ``    ``// rightmost 8 bits of the number. this will ``    ``// be converted into the leftmost 8 bits for the ``    ``// output (swapping) ``    ``leftmost_byte = (value & 0x000000FF) >> 0; `` ` `    ``// Similarly, get the right middle and left ``    ``// middle 8 bits which will become ``    ``// the left_middle bits in the output ``    ``left_middle_byle = (value & 0x0000FF00) >> 8; `` ` `    ``right_middle_byte = (value & 0x00FF0000) >> 16; `` ` `    ``// Get the leftmost 8 bits which will be the ``    ``// rightmost 8 bits of the output ``    ``rightmost_byte = (value & 0xFF000000) >> 24; `` ` `    ``// Left shift the 8 bits by 24 ``    ``// so that it is shifted to the ``    ``// leftmost end ``    ``leftmost_byte <<= 24; `` ` `    ``// Similarly, left shift by 16 ``    ``// so that it is in the left_middle ``    ``// position. i.e, it starts at the ``    ``// 9th bit from the left and ends at the ``    ``// 16th bit from the left ``    ``left_middle_byle <<= 16; `` ` `    ``right_middle_byte <<= 8; `` ` `    ``// The rightmost bit stays as it is ``    ``// as it is in the correct position ``    ``rightmost_byte <<= 0; `` ` `    ``// Result is the concatenation of all these values. ``    ``result = (leftmost_byte | left_middle_byle |``              ``right_middle_byte | rightmost_byte); `` ` `    ``return` `result; ``} `` ` `// Driver Code ``int` `main() ``{ `` ` `    ``// Consider a hexadecimal value ``    ``// given below. we are gonna convert ``    ``// this from big Endian to little Endian ``    ``// and vice versa. `` ` `    ``int` `big_Endian = 0x12345678; ``    ``int` `little_Endian = 0x78563412; `` ` `    ``int` `result1, result2; `` ` `    ``result1 = swap_Endians(big_Endian); `` ` `    ``result2 = swap_Endians(little_Endian); `` ` `    ``printf``(``"big Endian to little:"``           ``"0x%x\nlitle Endian to big: 0x%x\n"``,``            ``result1, result2); `` ` `    ``return` `0; ``} `` ` `// This code is contributed by SHUBHAMSINGH10`

## C

 `#include `` ` `// Function to swap a value from``// big Endian to little Endian and``// vice versa.`` ` `int` `swap_Endians(``int` `value)``{`` ` `    ``// This var holds the leftmost 8``    ``// bits of the output.`` ` `    ``int` `leftmost_byte;`` ` `    ``// This holds the left middle``    ``// 8 bits of the output`` ` `    ``int` `left_middle_byle;`` ` `    ``// This holds the right middle``    ``// 8 bits of the output`` ` `    ``int` `right_middle_byte;`` ` `    ``// This holds the rightmost``    ``// 8 bits of the output`` ` `    ``int` `rightmost_byte;`` ` `    ``// To store the result``    ``// after conversion`` ` `    ``int` `result;`` ` `    ``// Get the rightmost 8 bits of the number``    ``// by anding it 0x000000FF. since the last``    ``// 8 bits are all ones, the result will be the``    ``// rightmost 8 bits of the number. this will``    ``// be converted into the leftmost 8 bits for the``    ``// output (swapping)`` ` `    ``leftmost_byte = (value & 0x000000FF) >> 0;`` ` `    ``// Similarly, get the right middle and left``    ``// middle 8 bits which will become``    ``// the left_middle bits in the output`` ` `    ``left_middle_byle = (value & 0x0000FF00) >> 8;`` ` `    ``right_middle_byte = (value & 0x00FF0000) >> 16;`` ` `    ``// Get the leftmost 8 bits which will be the``    ``// rightmost 8 bits of the output`` ` `    ``rightmost_byte = (value & 0xFF000000) >> 24;`` ` `    ``// Left shift the 8 bits by 24``    ``// so that it is shifted to the``    ``// leftmost end`` ` `    ``leftmost_byte <<= 24;`` ` `    ``// Similarly, left shift by 16``    ``// so that it is in the left_middle``    ``// position. i.e, it starts at the``    ``// 9th bit from the left and ends at the``    ``// 16th bit from the left`` ` `    ``left_middle_byle <<= 16;`` ` `    ``right_middle_byte <<= 8;`` ` `    ``// The rightmost bit stays as it is``    ``// as it is in the correct position`` ` `    ``rightmost_byte <<= 0;`` ` `    ``// Result is the concatenation of all these values.`` ` `    ``result = (leftmost_byte | left_middle_byle``              ``| right_middle_byte | rightmost_byte);`` ` `    ``return` `result;``}`` ` `// Driver Code``int` `main()``{`` ` `    ``// Consider a hexadecimal value``    ``// given below. we are gonna convert``    ``// this from big Endian to little Endian``    ``// and vice versa.`` ` `    ``int` `big_Endian = 0x12345678;``    ``int` `little_Endian = 0x78563412;`` ` `    ``int` `result1, result2;`` ` `    ``result1 = swap_Endians(big_Endian);`` ` `    ``result2 = swap_Endians(little_Endian);`` ` `    ``printf``(``"big Endian to little: 0x%x\nlitle Endian to big: 0x%x\n"``,``           ``result1, result2);`` ` `    ``return` `0;``}`

## Java

 `// Java program to print the difference ``// of Alternate Nodes ``import` `java.util.*;`` ` `class` `GFG``{`` ` `// Function to swap a value from``// big Endian to little Endian and``// vice versa.``static` `int` `swap_Endians(``int` `value)``{`` ` `    ``// This var holds the leftmost 8``    ``// bits of the output.``    ``int` `leftmost_byte;`` ` `    ``// This holds the left middle``    ``// 8 bits of the output``    ``int` `left_middle_byle;`` ` `    ``// This holds the right middle``    ``// 8 bits of the output``    ``int` `right_middle_byte;`` ` `    ``// This holds the rightmost``    ``// 8 bits of the output``    ``int` `rightmost_byte;`` ` `    ``// To store the result``    ``// after conversion``    ``int` `result;`` ` `    ``// Get the rightmost 8 bits of the number``    ``// by anding it 0x000000FF. since the last``    ``// 8 bits are all ones, the result will be the``    ``// rightmost 8 bits of the number. this will``    ``// be converted into the leftmost 8 bits for the``    ``// output (swapping)``    ``leftmost_byte = (value & ``0x000000FF``) >> ``0``;`` ` `    ``// Similarly, get the right middle and left``    ``// middle 8 bits which will become``    ``// the left_middle bits in the output``    ``left_middle_byle = (value & ``0x0000FF00``) >> ``8``;`` ` `    ``right_middle_byte = (value & ``0x00FF0000``) >> ``16``;`` ` `    ``// Get the leftmost 8 bits which will be the``    ``// rightmost 8 bits of the output``    ``rightmost_byte = (value & ``0xFF000000``) >> ``24``;`` ` `    ``// Left shift the 8 bits by 24``    ``// so that it is shifted to the``    ``// leftmost end``    ``leftmost_byte <<= ``24``;`` ` `    ``// Similarly, left shift by 16``    ``// so that it is in the left_middle``    ``// position. i.e, it starts at the``    ``// 9th bit from the left and ends at the``    ``// 16th bit from the left``    ``left_middle_byle <<= ``16``;`` ` `    ``right_middle_byte <<= ``8``;`` ` `    ``// The rightmost bit stays as it is``    ``// as it is in the correct position``    ``rightmost_byte <<= ``0``;`` ` `    ``// Result is the concatenation of all these values.``    ``result = (leftmost_byte | left_middle_byle | ``              ``right_middle_byte | rightmost_byte);`` ` `    ``return` `result;``}`` ` `// Driver Code``public` `static` `void` `main(String[] args) ``{``    ``// Consider a hexadecimal value``    ``// given below. we are gonna convert``    ``// this from big Endian to little Endian``    ``// and vice versa.``    ``int` `big_Endian = ``0x12345678``;``    ``int` `little_Endian = ``0x78563412``;`` ` `    ``int` `result1, result2;`` ` `    ``result1 = swap_Endians(big_Endian);`` ` `    ``result2 = swap_Endians(little_Endian);`` ` `    ``System.out.printf(``"big Endian to little: 0x%x\n"` `+``                      ``"litle Endian to big: 0x%x\n"``,``                       ``result1, result2);``}``}`` ` `// This code is contributed by PrinciRaj1992 `

## Python3

 `# Function to swap a value from``# big Endian to little Endian and``# vice versa.``def` `swap_Endians(value):`` ` `    ``# Get the rightmost 8 bits of the number``    ``# by anding it 0x000000FF. since the last``    ``# 8 bits are all ones, the result will be the ``    ``# rightmost 8 bits of the number. this will``    ``# be converted into the leftmost 8 bits for the``    ``# output (swapping)`` ` `    ``leftmost_byte ``=` `(value & ``eval``(``'0x000000FF'``)) >> ``0`` ` `    ``# Similarly, get the right middle and left  ``    ``# middle 8 bits which will become``    ``# the left_middle bits in the output`` ` `    ``left_middle_byle ``=` `(value & ``eval``(``'0x0000FF00'``)) >> ``8`` ` `    ``right_middle_byte ``=` `(value & ``eval``(``'0x00FF0000'``))>> ``16`` ` `    ``# Get the leftmost 8 bits which will be the ``    ``# rightmost 8 bits of the output`` ` `    ``rightmost_byte ``=` `(value & ``eval``(``'0xFF000000'``))>> ``24`` ` `    ``# Left shift the 8 bits by 24``    ``# so that it is shifted to the ``    ``# leftmost end`` ` `    ``leftmost_byte <<``=` `24`` ` `    ``# Similarly, left shift by 16``    ``# so that it is in the left_middle``    ``# position. i.e, it starts at the``    ``# 9th bit from the left and ends at the``    ``# 16th bit from the left`` ` `    ``left_middle_byle <<``=` `16`` ` `    ``right_middle_byte <<``=` `8`` ` `    ``# The rightmost bit stays as it is``    ``# as it is in the correct position`` ` `    ``rightmost_byte <<``=` `0`` ` `    ``# Result is the concatenation of all these values`` ` `    ``result ``=` `(leftmost_byte | left_middle_byle ``                  ``| right_middle_byte | rightmost_byte)`` ` ` ` `    ``return` `result`` ` ` ` ` ` `# main function``if` `__name__ ``=``=` `'__main__'``:`` ` `    ``# Consider a hexadecimal value``    ``# given below. we are gonna convert``    ``# this from big Endian to little Endian``    ``# and vice versa.``    ``big_Endian ``=` `eval``(``'0x12345678'``)``    ``little_Endian ``=` `eval``(``'0x78563412'``)``     ` `    ``result1 ``=` `swap_Endians(big_Endian)`` ` `    ``result2 ``=` `swap_Endians(little_Endian)`` ` `    ``print``("big Endian to little: ``%` `s\nlitle Endian ``              ``to big: ``%` `s" ``%``(``hex``(result1), ``hex``(result2)))`

## C#

 `// C# program to print the difference ``// of Alternate Nodes ``using` `System;``     ` `class` `GFG``{`` ` `// Function to swap a value from``// big Endian to little Endian and``// vice versa.``static` `int` `swap_Endians(``int` `value)``{`` ` `    ``// This var holds the leftmost 8``    ``// bits of the output.``    ``int` `leftmost_byte;`` ` `    ``// This holds the left middle``    ``// 8 bits of the output``    ``int` `left_middle_byle;`` ` `    ``// This holds the right middle``    ``// 8 bits of the output``    ``int` `right_middle_byte;`` ` `    ``// This holds the rightmost``    ``// 8 bits of the output``    ``int` `rightmost_byte;`` ` `    ``// To store the result``    ``// after conversion``    ``int` `result;`` ` `    ``// Get the rightmost 8 bits of the number``    ``// by anding it 0x000000FF. since the last``    ``// 8 bits are all ones, the result will be the``    ``// rightmost 8 bits of the number. this will``    ``// be converted into the leftmost 8 bits for the``    ``// output (swapping)``    ``leftmost_byte = (value & 0x000000FF) >> 0;`` ` `    ``// Similarly, get the right middle and left``    ``// middle 8 bits which will become``    ``// the left_middle bits in the output``    ``left_middle_byle = (value & 0x0000FF00) >> 8;`` ` `    ``right_middle_byte = (value & 0x00FF0000) >> 16;`` ` `    ``// Get the leftmost 8 bits which will be the``    ``// rightmost 8 bits of the output``    ``rightmost_byte = (``int``)(value & 0xFF000000) >> 24;`` ` `    ``// Left shift the 8 bits by 24``    ``// so that it is shifted to the``    ``// leftmost end``    ``leftmost_byte <<= 24;`` ` `    ``// Similarly, left shift by 16``    ``// so that it is in the left_middle``    ``// position. i.e, it starts at the``    ``// 9th bit from the left and ends at the``    ``// 16th bit from the left``    ``left_middle_byle <<= 16;`` ` `    ``right_middle_byte <<= 8;`` ` `    ``// The rightmost bit stays as it is``    ``// as it is in the correct position``    ``rightmost_byte <<= 0;`` ` `    ``// Result is the concatenation of all these values.``    ``result = (leftmost_byte | left_middle_byle | ``              ``right_middle_byte | rightmost_byte);`` ` `    ``return` `result;``}`` ` `// Driver Code``public` `static` `void` `Main(String[] args) ``{``    ``// Consider a hexadecimal value``    ``// given below. we are gonna convert``    ``// this from big Endian to little Endian``    ``// and vice versa.``    ``int` `big_Endian = 0x12345678;``    ``int` `little_Endian = 0x78563412;`` ` `    ``int` `result1, result2;`` ` `    ``result1 = swap_Endians(big_Endian);`` ` `    ``result2 = swap_Endians(little_Endian);`` ` `    ``Console.Write(``"big Endian to little: 0x{0:x}\n"` `+``                    ``"litle Endian to big: 0x{1:x}\n"``,``                                   ``result1, result2);``}``}`` ` `// This code is contributed by Rajput-Ji`
Output:
```big Endian to little: 0x78563412
litle Endian to big: 0x12345678
```

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