Binary to decimal and vice-versa in python

Write Python code for converting a decimal number to it’s binary equivalent and vice-versa.

Example:

From decimal to binary
Input : 8
Output : 1 0 0 0


From binary to decimal
Input : 100
Output : 4

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Decimal to binary

Keep calling conversion function with n/2  till n > 1,
later perform n % 1 to get MSB of converted binary number.  
Example :- 7
1). 7/2 = Quotient = 3(grater than 1), Remainder = 1.
2). 3/2 = Quotient = 1(not grater than 1), Remainder = 1.
3). 1%2 = Remainder = 1.
Therefore, answer is 111.

# Function to print binary number for the  
# input decimal using recursion  
def decimalToBinary(n):  
  
    if(n > 1):  
        # divide with integral result  
        # (discard remainder)  
        decimalToBinary(n//2)  
  
      
    print(n%2, end=' ') 
      
      
  
# Driver code  
if __name__ == '__main__':  
    decimalToBinary(8)  
    print("\n") 
    decimalToBinary(18)  
    print("\n") 
    decimalToBinary(7)  
    print("\n") 

Output:

1 0 0 0 
1 0 0 1 0 
1 1 1

Decimal to binary using bin():

# Function to convert Decimal number 
# to Binary number 
  
def decimalToBinary(n): 
    return bin(n).replace("0b","") 
  
# Driver code 
if __name__ == '__main__': 
    print(decimalToBinary(8)) 
    print(decimalToBinary(18)) 
    print(decimalToBinary(7)) 

Output:

1000
10010
111

Binary to decimal

Example -: 1011
1). Take modulo of given binary number with 10. 
    (1011 % 10 = 1)
2). Multiply rem with 2 raised to the power
    it's position from right end. 
    (1 * 2^0)
    Note that we start counting position with 0. 
3). Add result with previously generated result.
    decimal = decimal + (1 * 2^0)
4). Update binary number by dividing it by 10.
    (1011 / 10 = 101)
5). Keep repeating upper steps till binary > 0.

Final Conversion -: (1 * 2^3) + (0 * 2^2) +
                 (1 * 2^1) + (1 * 2^0) = 11

# Function calculates the decimal equivalent  
# to given binary number 
  
def binaryToDecimal(binary): 
      
    binary1 = binary 
    decimal, i, n = 0, 0, 0
    while(binary != 0): 
        dec = binary % 10
        decimal = decimal + dec * pow(2, i) 
        binary = binary//10
        i += 1
    print(decimal)     
      
  
# Driver code 
if __name__ == '__main__': 
    binaryToDecimal(100) 
    binaryToDecimal(101) 
    binaryToDecimal(1001) 

Output:

4
5
9

Binary to decimal using int():

# Function to convert Binary number 
# to Decimal number 
  
def binaryToDecimal(n): 
    return int(n,2) 
  
  
# Driver code 
if __name__ == '__main__': 
    print(binaryToDecimal('100')) 
    print(binaryToDecimal('101')) 
    print(binaryToDecimal('1001')) 

Output:

4
5
9

This article is contributed by Pushpanjali Chauhan. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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My Personal Notes

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

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