BigInteger flipBit() Method in Java
Last Updated :
20 Mar, 2023
Prerequisite: BigInteger Basics
The java.math.BigInteger.flipBit(index) method returns a BigInteger which is used to flip a particular bit position in a BigInteger. This method Computes (bigInteger ^ (1<<n)). The bit at index n of binary representation of the bigInteger will be flipped. That is, if the bit position is 0 it will be converted to 1 and vice versa.
Syntax:
public BigInteger flipBit(int index)
Parameter:The method accepts one parameter index of integer type and refers to the position of the bit to be flipped.
Return Value: The method returns the bigInteger after flipping its bit at position index.
Throws: The method throws an ArithmeticException when the value of index is negative.
Examples:
Input: value = 2300 , index = 1
Output: 2302
Explanation:
Binary Representation of 2300 = 100011111100
bit at index 1 is 0 so flip the bit at index 1 and it becomes 1.
Now Binary Representation becomes 100011111110
and Decimal equivalent of 100011111110 is 2302
Input: value = 5482549 , index = 5
Output: 5482517
Below program illustrate flipBit(index) method of BigInteger.
Java
import java.math.*;
public class GFG {
public static void main(String[] args)
{
BigInteger biginteger = new BigInteger( "5482549" );
int i = 5 ;
BigInteger changedvalue = biginteger.flipBit(i);
String result = "After applying flipBit at index " + i +
" of " + biginteger+ " New Value is " + changedvalue;
System.out.println(result);
}
}
|
Output:
After applying flipBit at index 5 of 5482549 New Value is 5482517
Reference:https://docs.oracle.com/javase/7/docs/api/java/math/BigInteger.html#clearBit(int)
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