BigDecimal sqrt() Method in Java with Examples
Last Updated :
29 May, 2019
The java.math.BigDecimal.sqrt(MathContext mc) is an inbuilt function added in Java SE 9 & JDK 9 which returns BigDecimal value of square root of a BigDecimal on which sqrt() method is applied with rounding according to the context settings.
Syntax:
public BigDecimal sqrt(MathContext mc)
Parameters: This method accepts a parameter mc of type MathContext for context settings.
Return Value: This method returns an approximation to the square root of this with rounding according to the context settings.
Exception: The method throws ArithmeticException for following conditions.
- If BigDecimal number is less than zero.
- If an exact result is requested (Precision = 0) and there is no finite decimal expansion of the exact result.
- If the exact result cannot fit in Precision digits.
Note: This method is only available from JDK 9.
Below programs are used to illustrate the sqrt() method of BigDecimal:
Example 1:
import java.math.*;
public class GFG {
public static void main(String[] args)
{
BigDecimal a, squareRoot;
a = new BigDecimal( "100000000000000000000" );
MathContext mc
= new MathContext( 10 );
squareRoot = a.sqrt(mc);
System.out.println( "Square root value of " + a
+ " is " + squareRoot);
}
}
|
Output:
Square root value of 100000000000000000000 is 1.000000000E+10
Example 2: Showing Exception thrown by sqrt() method.
import java.math.*;
class GFG {
public static void main(String[] args)
{
BigDecimal a, squareRoot;
a = new BigDecimal( "-4" );
MathContext mc
= new MathContext( 10 );
try {
squareRoot = a.sqrt(mc);
System.out.println( "Square root"
+ " value of " + a
+ " is " + squareRoot);
}
catch (Exception e) {
System.out.println(e);
}
}
}
|
Output:
java.lang.ArithmeticException: Attempted square root of negative BigDecimal
References: https://docs.oracle.com/javase/9/docs/api/java/math/BigDecimal.html#sqrt-java.math.MathContext-
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...