BigDecimal movePointRight() Method in Java

Prerequisite : BigDecimal Basics

The java.math.BigDecimal.movePointRight(int n) method is used to move the decimal point of the current BigDecimal by n places to the right.

  • If n is non-negative, the call merely subtracts n from the scale.
  • If n is negative, the call is equivalent to movePointLeft(-n).

The BigDecimal returned by this method has value (this × 10n) and scale max(this.scale()-n, 0).


public BigDecimal movePointRight(int n)

Parameter: The method takes one parameter n of integer type which refers to the number of places by which the decimal point is required to be moved towards the right.

Return Value: The method returns the same BigDecimal value with the decimal point moved n places to the right.

Exception: The method throws an ArithmeticException if the scale overflows.


Input: value = 2300.9856, rightshift = 3
Output: 2300985.6
After shifting the decimal point of 2300.9856 by 3 places to right,
2300985.6 is obtained.
Alternate way: 2300.9856*10^(3)=2300985.6

Input: value = 35001, rightshift = 2
Output: 3500100

Below program illustrate the movePointRight() method of BigDecimal:





// Program to demonstrate movePointRight() method of BigDecimal 
import java.math.*;
public class GFG {
    public static void main(String[] args)
        // Create BigDecimal object
        BigDecimal bigdecimal = new BigDecimal("2300.9856");
        // Create a int i for decimal right move distance
        int i = 3;
        // Call movePointRight() method on BigDecimal by shift i
        BigDecimal changedvalue = bigdecimal.movePointRight(i);
        String result = "After applying decimal move right
        by move Distance " + i + " on " + bigdecimal + 
        " New Value is " + changedvalue;
        // Print result



After applying decimal move right by move Distance 3 on 2300.9856 New Value is 2300985.6


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