Basics of Relational model: Relational Model
Relational Algebra is a procedural query language which takes relations as an input and returns relation as an output. There are some basic operators which can be applied on relations to produce required results which we will discuss one by one. We will use STUDENT_SPORTS, EMPLOYEE and STUDENT relations as given in Table 1, Table 2 and Table 3 respectively to understand the various operators.
Table 1 : STUDENT_SPORTS
ROLL_NO | SPORTS |
1 | Badminton |
2 | Cricket |
2 | Badminton |
4 | Badminton |
Table 2 : EMPLOYEE
EMP_NO | NAME | ADDRESS | PHONE | AGE |
1 | RAM | DELHI | 9455123451 | 18 |
5 | NARESH | HISAR | 9782918192 | 22 |
6 | SWETA | RANCHI | 9852617621 | 21 |
4 | SURESH | DELHI | 9156768971 | 18 |
Table 3 : STUDENT
ROLL_NO | NAME | ADDRESS | PHONE | AGE |
1 | RAM | DELHI | 9455123451 | 18 |
2 | RAMESH | GURGAON | 9652431543 | 18 |
3 | SUJIT | ROHTAK | 9156253131 | 20 |
4 | SURESH | DELHI | 9156768971 | 18 |
Selection operator (σ): Selection operator is used to select tuples from a relation based on some condition. Syntax:
σ (Cond)(Relation Name)
Extract students whose age is greater than 18 from STUDENT relation given in Table 1
σ (AGE>18)(STUDENT)
RESULT:
ROLL_NO | NAME | ADDRESS | PHONE | AGE |
3 | SUJIT | ROHTAK | 9156253131 | 20 |
Projection Operator (∏): Projection operator is used to project particular columns from a relation. Syntax:
∏(Column 1,Column 2….Column n)(Relation Name)
Extract ROLL_NO and NAME from STUDENT relation given in Table 3
∏(ROLL_NO,NAME)(STUDENT)
RESULT:
ROLL_NO | NAME |
1 | RAM |
2 | RAMESH |
3 | SUJIT |
4 | SURESH |
Note: If resultant relation after projection has duplicate rows, it will be removed. For Example: ∏(ADDRESS)(STUDENT) will remove one duplicate row with value DELHI and return three rows.
Cross Product(X): Cross product is used to join two relations. For every row of Relation1, each row of Relation2 is concatenated. If Relation1 has m tuples and and Relation2 has n tuples, cross product of Relation1 and Relation2 will have m X n tuples. Syntax:
Relation1 X Relation2
To apply Cross Product on STUDENT relation given in Table 1 and STUDENT_SPORTS relation given in Table 2,
STUDENT X STUDENT_SPORTS
RESULT:
ROLL_NO | NAME | ADDRESS | PHONE | AGE | ROLL_NO | SPORTS |
1 | RAM | DELHI | 9455123451 | 18 | 1 | Badminton |
1 | RAM | DELHI | 9455123451 | 18 | 2 | Cricket |
1 | RAM | DELHI | 9455123451 | 18 | 2 | Badminton |
1 | RAM | DELHI | 9455123451 | 18 | 4 | Badminton |
2 | RAMESH | GURGAON | 9652431543 | 18 | 1 | Badminton |
2 | RAMESH | GURGAON | 9652431543 | 18 | 2 | Cricket |
2 | RAMESH | GURGAON | 9652431543 | 18 | 2 | Badminton |
2 | RAMESH | GURGAON | 9652431543 | 18 | 4 | Badminton |
3 | SUJIT | ROHTAK | 9156253131 | 20 | 1 | Badminton |
3 | SUJIT | ROHTAK | 9156253131 | 20 | 2 | Cricket |
3 | SUJIT | ROHTAK | 9156253131 | 20 | 2 | Badminton |
3 | SUJIT | ROHTAK | 9156253131 | 20 | 4 | Badminton |
4 | SURESH | DELHI | 9156768971 | 18 | 1 | Badminton |
4 | SURESH | DELHI | 9156768971 | 18 | 2 | Cricket |
4 | SURESH | DELHI | 9156768971 | 18 | 2 | Badminton |
4 | SURESH | DELHI | 9156768971 | 18 | 4 | Badminton |
Union (U): Union on two relations R1 and R2 can only be computed if R1 and R2 are union compatible (These two relation should have same number of attributes and corresponding attributes in two relations have same domain) . Union operator when applied on two relations R1 and R2 will give a relation with tuples which are either in R1 or in R2. The tuples which are in both R1 and R2 will appear only once in result relation. Syntax:
Relation1 U Relation2
Find person who are either student or employee, we can use Union operator like:
STUDENT U EMPLOYEE
RESULT:
ROLL_NO | NAME | ADDRESS | PHONE | AGE |
1 | RAM | DELHI | 9455123451 | 18 |
2 | RAMESH | GURGAON | 9652431543 | 18 |
3 | SUJIT | ROHTAK | 9156253131 | 20 |
4 | SURESH | DELHI | 9156768971 | 18 |
5 | NARESH | HISAR | 9782918192 | 22 |
6 | SWETA | RANCHI | 9852617621 | 21 |
Minus (-): Minus on two relations R1 and R2 can only be computed if R1 and R2 are union compatible. Minus operator when applied on two relations as R1-R2 will give a relation with tuples which are in R1 but not in R2. Syntax:
Relation1 - Relation2
Find person who are student but not employee, we can use minus operator like:
STUDENT - EMPLOYEE
RESULT:
ROLL_NO | NAME | ADDRESS | PHONE | AGE |
2 | RAMESH | GURGAON | 9652431543 | 18 |
3 | SUJIT | ROHTAK | 9156253131 | 20 |
Rename(ρ): Rename operator is used to give another name to a relation. Syntax:
ρ(Relation2, Relation1)
To rename STUDENT relation to STUDENT1, we can use rename operator like:
ρ(STUDENT1, STUDENT)
If you want to create a relation STUDENT_NAMES with ROLL_NO and NAME from STUDENT, it can be done using rename operator as:
ρ(STUDENT_NAMES, ∏(ROLL_NO, NAME)(STUDENT))
Extended Relational Algebra Operators Overview of Relational Algebra Operators
Previous Year Gate Questions
http://quiz.geeksforgeeks.org/gate-gate-cs-2012-question-50/
http://quiz.geeksforgeeks.org/gate-gate-cs-2012-question-43/
Article contributed by Sonal Tuteja. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above
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