atomic.SwapUintptr() Function in Golang With Examples
In Go language, atomic packages supply lower-level atomic memory that is helpful is implementing synchronization algorithms. The SwapUintptr() function in Go language is used to atomically store new value into *addr and returns the previous *addr value. This function is defined under the atomic package. Here, you need to import “sync/atomic” package in order to use these functions.
Syntax:
func SwapUintptr(addr *uintptr, new uintptr) (old uintptr)
Here, addr indicates address. And new is the new uintptr value and old is the older uintptr value.
Note: (*uintptr) is the pointer to a uintptr value. And uintptr is an integer type that is too large that it can contain the bit pattern of any pointer.
Return Value: It stores the new uintptr value into the *addr and returns the previous *addr value.
Example 1:
package main
import (
"fmt"
"sync/atomic"
)
func main() {
var x uintptr = 96464646466757
var old_val = atomic.SwapUintptr(&x,
21863567864)
fmt.Println( "Stored new value: " ,
x, ", Old value: " , old_val)
}
|
Output:
Stored new value: 21863567864, Old value: 96464646466757
Example 2:
package main
import (
"fmt"
"sync/atomic"
)
func main() {
var m uintptr = 4235564747474
var n uintptr = 2567891937466
var oldVal1 = atomic.SwapUintptr(&m, 4235564747474)
var oldVal2 = atomic.SwapUintptr(&n, 7454545419024)
fmt.Println((oldVal1) == m)
fmt.Println((oldVal2) == n)
}
|
Output:
true
false
Here, the oldVal1 is equal to “m” as the new value to be stored in the *addr is same as old value so, true is returned but oldVal2 is not equal to “n” as there the old value is not similar to the newly assigned value hence, false is returned.
Last Updated :
01 Apr, 2020
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