Array sum after dividing numbers from previous

Find the sum of number of series after dividing the element of array from previous element.

Examples:

```Input : 3 7 9 10 12 18
Explanation:  3 + 7/3 + 9/7 + 10/9 +
12/10 + 18/12 = 9 (taking only integer
part)
Output : 9

Input : 1 12 24 30 60
Output : 18
```

Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: We take elements in an array and divide the element from previous element. We do this process for all the elements of an array except very first element. Add the result after division and very first element.

Note: If any element is zero in an array then it fails to do the task and return minus one.

C++

 `// C++  program for divide and ` `// sum the number of series ` `#include ` `using` `namespace` `std; ` ` `  `int` `divideAndSum(``int` `arr[], ``int` `n) ` `{ ` `    ``int` `sum = 0; ` `    ``for` `(``int` `i = 0; i < n; i++) { ` `         `  `        ``// checking whether element  ` `        ``// is zero or not ` `        ``if` `(arr[i] == 0)  ` `            ``return` `-1; ` `         `  `        ``if` `(i == 0) ` `            ``sum += arr[i]; ` `        ``else` ` `  `            ``// divide element from ` `            ``// previous element ` `            ``sum += arr[i] / arr[i - 1]; ` `    ``} ` `     `  `    ``return` `sum; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `arr[] = { 3, 7, 9, 10, 12, 18 }; ` `    ``int` `n = ``sizeof``(arr)/``sizeof``(arr[0]); ` `    ``cout << divideAndSum(arr, n); ` `    ``return` `0; ` `} `

Java

 `// java program for divide and ` `// sum the number of series ` `import` `java.io.*; ` ` `  `class` `GFG  ` `{ ` `     `  `    ``static` `int` `divideAndSum(``int` `arr[], ``int` `n) ` `    ``{ ` `        ``int` `sum = ``0``; ` `        ``for` `(``int` `i = ``0``; i < n; i++) { ` `             `  `            ``// checking whether element  ` `            ``// is zero or not ` `            ``if` `(arr[i] == ``0``)  ` `                ``return` `-``1``; ` `             `  `            ``if` `(i == ``0``) ` `                ``sum += arr[i]; ` `            ``else` `     `  `                ``// divide element from ` `                ``// previous element ` `                ``sum += arr[i] / arr[i - ``1``]; ` `        ``} ` `         `  `        ``return` `sum; ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main (String[] args)  ` `    ``{ ` `        ``int` `arr[] = { ``3``, ``7``, ``9``, ``10``, ``12``, ``18` `}; ` `        ``int` `n = arr.length; ` `        ``System.out.println( divideAndSum(arr, n)); ` ` `  `    ``} ` `} ` ` `  `// This code is contributed by vt_m `

Python3

 `# Python 3 program for divide and ` `# sum the number of series ` ` `  `def` `divideAndSum(arr, n): ` `  `  `    ``sum` `=` `0`  `    ``for` `i ``in` `range``(``0``,n):   ` `         `  `         ``# checking whether element  ` `         ``# is zero or not ` `        ``if` `(arr[i] ``=``=` `0``):  ` `            ``return` `-``1`  `         `  `        ``if` `(i ``=``=` `0``): ` `            ``sum` `+``=` `arr[i]  ` `        ``else``: ` ` `  `                     ``# divide element from ` `             ``# previous element ` `             ``sum` `+``=` `int``(arr[i] ``/` `arr[i ``-` `1``])  ` `      `  `     `  `    ``return` `int``(``sum``)  ` `  `  ` `  `# Driver code ` `arr ``=`   `[``3``, ``7``, ``9``, ``10``, ``12``, ``18``]    ` ` `  `n ``=` `len``(arr) ` `print``(divideAndSum(arr, n)) ` ` `  `# This code is contributed by ` `# Smitha Dinesh Semwal  `

C#

 `// C# program for divide and ` `// sum the number of series ` `using` `System; ` ` `  `class` `GFG  ` `{ ` `     `  `    ``static` `int` `divideAndSum(``int` `[]arr, ``int` `n) ` `    ``{ ` `        ``int` `sum = 0; ` `        ``for` `(``int` `i = 0; i < n; i++) { ` `             `  `            ``// checking whether element  ` `            ``// is zero or not ` `            ``if` `(arr[i] == 0)  ` `                ``return` `-1; ` `             `  `            ``if` `(i == 0) ` `                ``sum += arr[i]; ` `            ``else` `     `  `                ``// divide element from ` `                ``// previous element ` `                ``sum += arr[i] / arr[i - 1]; ` `        ``} ` `         `  `        ``return` `sum; ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main ()  ` `    ``{ ` `        ``int` `[]arr = { 3, 7, 9, 10, 12, 18 }; ` `        ``int` `n = arr.Length; ` `        ``Console.WriteLine( divideAndSum(arr, n)); ` ` `  `    ``} ` `} ` ` `  `// This code is contributed by vt_m `

PHP

 ` `

Output:

`9`

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