Given the P, B and H are the perpendicular, base and hypotenuse respectively of a right angled triangle. The task is to find the area of the incircle of radius r as shown below:
Examples:
Input: P = 3, B = 4, H = 5
Output: 3.14Input: P = 5, B = 12, H = 13
Output: 12.56
Approach: Formula for calculating the inradius of a right angled triangle can be given as r = ( P + B – H ) / 2.
And we know that the area of a circle is PI * r2 where PI = 22 / 7 and r is the radius of the circle.
Hence the area of the incircle will be PI * ((P + B – H) / 2)2.
Below is the implementation of the above approach:
C
// C program to find the area of // incircle of right angled triangle #include <stdio.h> #define PI 3.14159265 // Function to find area of // incircle float area_inscribed(float P, float B, float H) { return ((P + B - H) * (P + B - H) * (PI / 4)); } // Driver code int main() { float P = 3, B = 4, H = 5; printf("%f", area_inscribed(P, B, H)); return 0; } |
Java
// Java code to find the area of inscribed // circle of right angled triangle import java.lang.*; class GFG { static double PI = 3.14159265; // Function to find the area of // inscribed circle public static double area_inscribed(double P, double B, double H) { return ((P + B - H) * (P + B - H) * (PI / 4)); } // Driver code public static void main(String[] args) { double P = 3, B = 4, H = 5; System.out.println(area_inscribed(P, B, H)); } } |
Python3
# Python3 code to find the area of inscribed # circle of right angled triangle PI = 3.14159265 # Function to find the area of # inscribed circle def area_inscribed(P, B, H): return ((P + B - H)*(P + B - H)*(PI / 4)) # Driver code P = 3B = 4H = 5print(area_inscribed(P, B, H)) |
C#
// C# code to find the area of // inscribed circle // of right angled triangle using System; class GFG { static double PI = 3.14159265; // Function to find the area of // inscribed circle public static double area_inscribed(double P, double B, double H) { return ((P + B - H) * (P + B - H) * (PI / 4)); } // Driver code public static void Main() { double P = 3.0, B = 4.0, H = 5.0; Console.Write(area_inscribed(P, B, H)); } } |
PHP
<?php // PHP program to find the // area of inscribed // circle of right angled triangle $PI = 3.14159265; // Function to find area of // inscribed circle function area_inscribed($P, $B, $H) { global $PI; return (($P + $B - $H)*($P + $B - $H)* ($PI / 4)); } // Driver code $P=3; $B=4; $H=5; echo(area_inscribed($P, $B, $H)); ?> |
3.141593
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