Given an integer C which is the length of the hypotenuse of a right angled triangle of a circumcircle passing through the centre of the circumcircle. The task is to find the area of the circumcircle.
Input: C = 8
Input: C = 10
Approach: Since the hypotenuse C passes through the center of the circle, the radius of the circle will be C / 2.
And we know that the area of a circle is PI * r2 where PI = 22 / 7 and r is the radius of the circle.
Hence the area of the circumcircle will be PI * (C / 2)2 i.e. PI * C2 / 4.
Below is the implementation of the above approach:
- Program to calculate area of Circumcircle of an Equilateral Triangle
- Area of Incircle of a Right Angled Triangle
- Find all sides of a right angled triangle from given hypotenuse and area | Set 1
- Find the height of a right-angled triangle whose area is X times its base
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- Area of the circumcircle of any triangles with sides given
- Find the dimensions of Right angled triangle
- Check whether right angled triangle is valid or not for large sides
- Check if a right-angled triangle can be formed by moving any one of the coordinates
- Area of Reuleaux Triangle
- Check if right triangle possible from given area and hypotenuse
- Area of a triangle inside a parallelogram
- Program to find area of a triangle
- Find the coordinates of a triangle whose Area = (S / 2)
- Area of the Largest Triangle inscribed in a Hexagon
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Improved By : Shivi_Aggarwal