Given an integer C which is the length of the hypotenuse of a right angled triangle of a circumcircle passing through the centre of the circumcircle. The task is to find the area of the circumcircle.
Input: C = 8
Input: C = 10
Approach: Since the hypotenuse C passes through the center of the circle, the radius of the circle will be C / 2.
And we know that the area of a circle is PI * r2 where PI = 22 / 7 and r is the radius of the circle.
Hence the area of the circumcircle will be PI * (C / 2)2 i.e. PI * C2 / 4.
Below is the implementation of the above approach:
- Program to calculate area of Circumcircle of an Equilateral Triangle
- Area of Incircle of a Right Angled Triangle
- Find all sides of a right angled triangle from given hypotenuse and area | Set 1
- Find the height of a right-angled triangle whose area is X times its base
- Number of possible pairs of Hypotenuse and Area to form right angled triangle
- Area of the circumcircle of any triangles with sides given
- Find the dimensions of Right angled triangle
- Check whether right angled triangle is valid or not for large sides
- Check if a right-angled triangle can be formed by moving any one of the coordinates
- Area of Reuleaux Triangle
- Find the coordinates of a triangle whose Area = (S / 2)
- Area of a triangle inside a parallelogram
- Program to find area of a triangle
- Check if right triangle possible from given area and hypotenuse
- Area of the Largest Triangle inscribed in a Hexagon
If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.
Improved By : Shivi_Aggarwal