Given an integer a as the side of the square ABCD. The task is to find the area of the leaf AECFA inside the square as shown below:
Examples:
Input: a = 7
Output: 28Input: a = 21
Output: 252
Approach: To calculate the area of the leaf, first find the area of the half leaf AECA, which can be given as:
Area of half leaf = Area of quadrant AECDA – Area of right triangle ACD.
Thus, Area of half leaf = ( PI * a * a / 4 ) – a * a / 2 where PI = 22 / 7 and a is the side of the square.
Hence, the area of full leaf will be ( PI * a * a / 2 ) – a * a
On taking a * a common we get, Area of leaf = a * a ( PI / 2 – 1 )
Below is the implementation of the above approach:
// C program to find the area of // leaf inside a square #include <stdio.h> #define PI 3.14159265 // Function to find area of // leaf float area_leaf( float a)
{ return (a * a * (PI / 2 - 1));
} // Driver code int main()
{ float a = 7;
printf ( "%f" ,
area_leaf(a));
return 0;
} |
// Java code to find the area of // leaf inside a square import java.lang.*;
class GFG {
static double PI = 3.14159265 ;
// Function to find the area of
// leaf
public static double area_leaf( double a)
{
return (a * a * (PI / 2 - 1 ));
}
// Driver code
public static void main(String[] args)
{
double a = 7 ;
System.out.println(area_leaf(a));
}
} |
# Python3 code to find the area of leaf # inside a square PI = 3.14159265
# Function to find the area of # leaf def area_leaf( a ):
return ( a * a * ( PI / 2 - 1 ) )
# Driver code a = 7
print (area_leaf( a ))
|
// C# code to find the area of // leaf // inside square using System;
class GFG {
static double PI = 3.14159265;
// Function to find the area of
// leaf
public static double area_leaf( double a)
{
return (a * a * (PI / 2 - 1));
}
// Driver code
public static void Main()
{
double a = 7;
Console.Write(area_leaf(a));
}
} |
<?php // PHP program to find the // area of leaf // inside a square $PI = 3.14159265;
// Function to find area of // leaf function area_leaf( $a )
{ global $PI ;
return ( $a * $a * ( $PI / 2 - 1 ) );
} // Driver code $a = 7;
echo (area_leaf( $a ));
?> |
<script> // Javascript program to find the area of // leaf inside a square const PI = 3.14159265; // Function to find area of // leaf function area_leaf(a)
{ return (a * a * (PI / 2 - 1));
} // Driver code let a = 7; document.write(Math.round(area_leaf(a))); // This code is contributed by souravmahato348 </script> |
28
Time complexity: O(1), since there is no loop or recursion.
Auxiliary Space: O(1), since no extra space has been taken.