Aptitude | Trigonometry & Height and Distances | Question 3

If tan (x+y) tan (x-y) = 1, then find tan (2x/3)?
(A) 2/√3
(B) 1/2
(C) 1/√2
(D) 1/√3


Answer: (D)

Explanation: tanA = cotB,
tanA*tan B = 1
So, A +B = 90^o
(x+y)+(x-y) = 90^o, 2x = 90^o , x = 45^o
Tan (2x/3) = tan 30^o = 1/√3


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