Aptitude | Trigonometry & Height and Distances | Question 3

If tan (x+y) tan (x-y) = 1, then find tan (2x/3)?

(A)

1/√3

(B)

1/2

(C)

1/√2

(D)

2/√3

Answer: (A)

Explanation:

tanA = cotB, 
tanA*tan B = 1
So, A +B = 90^o
(x+y)+(x-y) = 90^o, 2x = 90^o , x = 45^o
Tan (2x/3) = tan 30^o = 1/√3

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