Aptitude | Simplification and Approximation | Question 10

b – [b -(a+b) – {b – (b – a+b)} + 2a] = ?
(A) 2a
(B) a+b
(C) b-2a
(D) 0


Answer: (D)

Explanation: BODMAS rule

b – [b -(a+b) – {b – (2b – a)} + 2a]

b-[b-a-b-{-b+a}+2a]

b-[b-a-b-a+b+2a]

b-b=0

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