Aptitude | Progressions | Question 8

Calculate the sum of given series: 1/3, 1/9, 1/27, 1/81……………..

(A)

1/4

(B)

1/3

(C)

1/2

(D)

1

Answer: (C)

Explanation:

The given series is an infinite GP, whose sum is given by Sn=a/(r-1) Where, a=first term of series, r=common ratio. Therefore, Sn=(1/3)/(1-1/3) Sn=1/2

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