X is a positive 4 digit number. Find the largest possible value of X, such that on dividing with 5, 6, 7 it gives the remainder zero.
(A)
9980
(B)
9870
(C)
9540
(D)
9640
Answer: (B)
Explanation:
The required number must be divisible by L.C.M. of 5,6 and 7.
L.C.M. of 5, 6 and 7 = 5 x 6 x 7 = 210
Let us divide 9999 by 210.
210) 9999 (47
840
----
1599
1470
----
129
Required number = 9999 – 129 = 9870Quiz of this Question
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