Aptitude | Arithmetic Aptitude 4 | Question 2
How many terms are there in 3,9,27,81……..531441?
(A) 25
(B) 12
(C) 13
(D) 14
Answer: (B)
Explanation:
3, 9, 27, 81..............531441 form a G.P. with a = 3 and r = 9/3 = 3 Let the number of terms be n
According to the formula,
Nth term of the G.P is represented as Tn = a x rn-1
Then 3 x 3n-1 = 531441 ∴ 3n = 312 ∴ n = 12
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