Aptitude | Arithmetic Aptitude 4 | Question 2
How many terms are there in 3,9,27,81……..531441?
3, 9, 27, 81..............531441 form a G.P.
with a = 3 and r = 9/3 = 3
Let the number of terms be n
According to the formula,
Nth term of the G.P is represented as Tn = a x rn-1
Then 3 x 3n-1 = 531441
∴ 3n = 312
∴ n = 12
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