The present ages of A, B and C are in proportions 4:5:9. Nine years ago, sum of their ages was 45 years. Find their present ages in years
Explanation: Let the current ages of A, B and C be ax years, 5x years and 9x respectively.
Then (4x-9) + (5x-9) + (9x-9) =45 ∴ 18x – 27 = 45 ∴ 18x = 72 ∴ x = 4
Present ages of A, B and C are 4x = 16, 5x = 20, 9x = 36 respectively.
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