# Aptitude | Algebra | Question 7

If x^{1/3} + y^{1/3} – z^{1/3} = 0 then value of (x + y – z)^{3} + 27xyz is**(A)** 8**(B)** 2**(C)** 0**(D)** 6**Answer:** **(C)****Explanation:**

x^{1/3}+ y^{1/3}= z^{1/3}Now cubing both sides we get x + 3x^{1/3}y^{1/3}(x^{1/3}+ y^{1/3}) + y = z or, (x + y - z) = -3x^{1/3}y^{1/3}z^{1/3}Cubing again both sides, (x + y - z) = -27xyz. So answer is zero