Angle subtended by the chord to center of the circle when the angle subtended by the another equal chord of a congruent circle is given
Given are two congruent circles with two equal chords. The angle subtended to the center from the chord of one of the circles is given. The task is to find the angle subtended by the chord to the center of another circle.
Input: z = 48 Output: 48 degrees Input: z = 93 Output: 93 degrees
- In triangle AOB and PXQ
AO = PX(radii of congruent circles) BO = QX(radii of congruent circles) AB = PQ(equal chords)
- So, triangle AOB is congruent with triangle PXQ
- So, angle AOB = angle PXQ
Equal chords of congruent circles subtend equal angles at their centers.
Below is the implementation of the above approach:
The angle is 48 degrees