Given a number n, the task is to print its Aliquot Sequence. Aliquot Sequence of a number starts with itself, remaining terms of the sequence are sum of proper divisors of immediate previous term. For example, Aliquot Sequence for 10 is 10, 8, 7, 1, 0. The sequence may repeat. For example, for 6, we have an infinite sequence of all 6s. In such cases we print the repeating number and stop.
Input: n = 10 Output: 10 8 7 1 0 Sum of proper divisors of 10 is 5 + 2 + 1 = 8. Sum of proper divisors of 8 is 4 + 2 + 1 = 7. Sum of proper divisors of 7 is 1 Sum of proper divisors of 1 is 0 Note that there is no proper divisor of 1. Input : n = 6 Output : 6 Repeats with 6 Input : n = 12 Output : 12 16 15 9 4 3 1 0
- Numbers which have repeating Aliquot sequence of length 1 are called Perfect Numbers. For example 6, sum of its proper divisors is 6.
- Numbers which have repeating Aliquot sequence of length 2 are called Amicable numbers. For example 220 is a Amicable Number.
- Numbers which have repeating Aliquot sequence of length 3 are called sociable number.
- It is conjectured that every aliquot sequence ends in one of the following ways
- with a prime number which in turn ends with 1 and then 0.
- a perfect number
- a set of amicable or sociable numbers.
The solution mainly lies in the calculation of sum of all the proper divisors of the previous term.
- If we observe carefully, the divisors of the number n are present in pairs. For example if n = 100, then all the pairs of divisors are: (1,100), (2,50), (4,25), (5,20), (10,10)
- Using this fact efficiently compute divisors. While checking divisors we will have to be careful if there are two equal divisors as in case of (10, 10).
- In such case we will take only one of them in calculation of sum. This sum will contain sum of all the possible divisors so we have to subtract the number n from the sum of all divisors to get the sum of proper divisors.
We can generate the sequence by first printing the number n and then calculating the next terms using sum of proper divisors. When we compute next term, we check if we have already seen this term or not. If the term appears again, we have repeating sequence. We print the same and break the loop.
12 16 15 9 4 3 1 0
This article is contributed by Harsh Agarwal. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to email@example.com. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
- Removing a number from array to make it Geometric Progression
- Count digits in given number N which divide N
- Find the prime numbers which can written as sum of most consecutive primes
- Keith Number
- Efficient program to print all prime factors of a given number
- Number of Permutations such that no Three Terms forms Increasing Subsequence
- Check if the first and last digit of the smallest number forms a prime
- Print all substring of a number without any conversion
- Complement of a number with any base b
- Check if Decimal representation of an Octal number is divisible by 7