# Algorithms | Recursion | Question 7

• Difficulty Level : Easy
• Last Updated : 03 Jul, 2020

What does the following function do?

 `int` `fun(unsigned ``int` `n)``{``    ``if` `(n == 0 || n == 1)``        ``return` `n;`` ` `    ``if` `(n%3 != 0)``        ``return` `0;`` ` `    ``return` `fun(n/3);``}`

(A) It returns 1 when n is a multiple of 3, otherwise returns 0
(B) It returns 1 when n is a power of 3, otherwise returns 0
(C) It returns 0 when n is a multiple of 3, otherwise returns 1
(D) It returns 0 when n is a power of 3, otherwise returns 1

Explanation: Lets solve with example, n = 27 which power of 3.
First time if condition is false as n is neither equal to 0 nor equal to 1 then 27%3 = 0.
Here, again if condition false because it is equal to 0.
Then fun(27/3) will call.

Second time if condition is false as n is neither equal to 0 nor equal to 1 then 9%3 = 0.
Here again if condition false because it is equal to 0.

Then fun (9/3) will call and third time if condition is false as n is neither equal to 0 nor equal to 1 then 3%3 = 0.
Here again if condition false because it is equal to 0.

Then fun(3/3) will call here n==1 if condition gets true and it return n i.e. 1.

Option (B) is correct.

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