Algorithms Quiz | SP2 Contest 1 | Question 35

8 years ago, the average age of a family of 6 members was 22 years. Two children having been born (with age difference of 3 years), the present average age of the family is the same. The present age of the youngest child is:

(A) 1
(B) 2
(C) 3
(D) 4


Answer: (A)

Explanation: Total age of 6 members, 8 years ago = (22 x 6) years = 132 years.
Total age of 6 members now = [132 + (8 x 6)] years = 180 years.
Total age of 8 members now = (22 x 8) years = 176 years.
Sum of the ages of 2 children = (180 – 176) years = 4 years.
Let the age of the younger child be x years.
Then, age of the elder child = (x+3) years. So,
=> x+(x+3) = 4
=> x = 1
Age of younger child = 1 year.

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