Algorithms | Divide and Conquer | Question 2
Consider the following C program
int main() { int x, y, m, n; scanf ("%d %d", &x, &y); /* x > 0 and y > 0 */ m = x; n = y; while (m != n) { if(m>n) m = m - n; else n = n - m; } printf("%d", n); } |
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What does the program compute? (GATE CS 2004)
(A) x + y using repeated subtraction
(B) x mod y using repeated subtraction
(C) the greatest common divisor of x and y
(D) the least common multiple of x and y
Answer: (C)
Explanation: This is an implementation of Euclid’s algorithm to find GCD
