Write a function Add() that returns sum of two integers. The function should not use any of the arithmetic operators (+, ++, –, -, .. etc).

Sum of two bits can be obtained by performing XOR (^) of the two bits. Carry bit can be obtained by performing AND (&) of two bits.

Above is simple Half Adder logic that can be used to add 2 single bits. We can extend this logic for integers. If x and y don’t have set bits at same position(s), then bitwise XOR (^) of x and y gives the sum of x and y. To incorporate common set bits also, bitwise AND (&) is used. Bitwise AND of x and y gives all carry bits. We calculate (x & y) << 1 and add it to x ^ y to get the required result.

## C

// C Program to add two numbers // without using arithmetic operator #include<stdio.h> int Add(int x, int y) { // Iterate till there is no carry while (y != 0) { // carry now contains common //set bits of x and y int carry = x & y; // Sum of bits of x and y where at //least one of the bits is not set x = x ^ y; // Carry is shifted by one so that adding // it to x gives the required sum y = carry << 1; } return x; } int main() { printf("%d", Add(15, 32)); return 0; }

## Java

// Java Program to add two numbers // without using arithmetic operator import java.io.*; class GFG { static int Add(int x, int y) { // Iterate till there is no carry while (y != 0) { // carry now contains common // set bits of x and y int carry = x & y; // Sum of bits of x and // y where at least one // of the bits is not set x = x ^ y; // Carry is shifted by // one so that adding it // to x gives the required sum y = carry << 1; } return x; } // Driver code public static void main(String arg[]) { System.out.println(Add(15, 32)); } } // This code is contributed by Anant Agarwal.

## Python3

# Python3 Program to add two numbers # without using arithmetic operator def Add(x, y): # Iterate till there is no carry while (y != 0): # carry now contains common # set bits of x and y carry = x & y # Sum of bits of x and y where at # least one of the bits is not set x = x ^ y # Carry is shifted by one so that # adding it to x gives the required sum y = carry << 1 return x print(Add(15, 32)) # This code is contributed by # Smitha Dinesh Semwal

## C#

// C# Program to add two numbers // without using arithmetic operator using System; class GFG { static int Add(int x, int y) { // Iterate till there is no carry while (y != 0) { // carry now contains common // set bits of x and y int carry = x & y; // Sum of bits of x and // y where at least one // of the bits is not set x = x ^ y; // Carry is shifted by // one so that adding it // to x gives the required sum y = carry << 1; } return x; } // Driver code public static void Main() { Console.WriteLine(Add(15, 32)); } } // This code is contributed by vt_m.

## PHP

<?php // PHP Program to add two numbers // without using arithmetic operator function Add( $x, $y) { // Iterate till there is // no carry while ($y != 0) { // carry now contains common //set bits of x and y $carry = $x & $y; // Sum of bits of x and y where at //least one of the bits is not set $x = $x ^ $y; // Carry is shifted by one // so that adding it to x // gives the required sum $y = $carry << 1; } return $x; } // Driver Code echo Add(15, 32); // This code is contributed by anuj_67. ?>

**Output :**

47

Following is the recursive implementation for the same approach.

int Add(int x, int y) { if (y == 0) return x; else return Add( x ^ y, (x & y) << 1); }

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