AbstractSet toArray() method in Java with Example
The toArray() method of Java AbstractSet is used to form an array of the same elements as that of the AbstractSet. Basically, it copies all the element from a AbstractSet to a new array.
Syntax:
Object[] arr = AbstractSet.toArray()
Parameters: The method does not take any parameters.
Return Value: The method returns an array containing the elements similar to the AbstractSet.
Below programs illustrate the AbstractSet.toArray() method:
Program 1:
import java.util.*;
public class AbstractSetDemo {
public static void main(String args[])
{
AbstractSet<String>
abs_col = new TreeSet<String>();
abs_col.add( "Welcome" );
abs_col.add( "To" );
abs_col.add( "Geeks" );
abs_col.add( "For" );
abs_col.add( "Geeks" );
System.out.println( "The AbstractSet: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSet: [For, Geeks, To, Welcome]
The array is:
For
Geeks
To
Welcome
Program 2:
import java.util.*;
public class AbstractSetDemo {
public static void main(String args[])
{
AbstractSet<Integer>
abs_col = new TreeSet<Integer>();
abs_col.add( 10 );
abs_col.add( 15 );
abs_col.add( 30 );
abs_col.add( 20 );
abs_col.add( 5 );
abs_col.add( 25 );
System.out.println( "The AbstractSet: "
+ abs_col);
Object[] arr = abs_col.toArray();
System.out.println( "The array is:" );
for ( int j = 0 ; j < arr.length; j++)
System.out.println(arr[j]);
}
}
|
Output:
The AbstractSet: [5, 10, 15, 20, 25, 30]
The array is:
5
10
15
20
25
30
Last Updated :
24 Dec, 2018
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