AbstractSequentialList size() method in Java with Example
Last Updated :
24 Dec, 2018
The size() method of AbstractSequentialList in Java is used to get the size for this instance of the AbstractSequentialList. It returns an integer value which is the size for this instance of the AbstractSequentialList.
Syntax:
public int size()
Parameters: This method does not accepts any parameter.
Returns: The method returns an integer value which is the size for this instance of the AbstractSequentialList.
Below examples illustrates the AbstractSequentialList.size() method:
Example 1:
import java.util.*;
public class GFG {
public static void main(String[] args)
{
AbstractSequentialList<Integer> arr
= new LinkedList<Integer>();
arr.add( 1 );
arr.add( 2 );
arr.add( 3 );
arr.add( 4 );
System.out.println( "AbstractSequentialList: "
+ arr);
System.out.println( "Size: "
+ arr.size());
}
}
|
Output:
AbstractSequentialList: [1, 2, 3, 4]
Size: 4
Example 2:
import java.util.*;
public class GFG {
public static void main(String[] args)
{
AbstractSequentialList<String> arr
= new LinkedList<String>();
arr.add( "Geeks" );
arr.add( "For" );
arr.add( "ForGeeks" );
arr.add( "GeeksForGeeks" );
System.out.println( "AbstractSequentialList: "
+ arr);
System.out.println( "Size: "
+ arr.size());
}
}
|
Output:
AbstractSequentialList: [Geeks, For, ForGeeks, GeeksForGeeks]
Size: 4
Like Article
Suggest improvement
Share your thoughts in the comments
Please Login to comment...