AbstractList iterator() method in Java with Examples
Last Updated :
26 Nov, 2018
The iterator() method of java.util.AbstractList class is used to return an iterator over the elements in this list in proper sequence.
This implementation returns a straightforward implementation of the iterator interface, relying on the backing list’s size(), get(int), and remove(int) methods.
Syntax:
public Iterator iterator()
Returns Value: This method returns an iterator over the elements in this list in proper sequence.
Below are the examples to illustrate the iterator() method.
Example 1:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<Integer>
arrlist1 = new ArrayList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "ArrayList : "
+ arrlist1);
Iterator it = arrlist1.iterator();
while (it.hasNext()) {
System.out.println( "Value is : "
+ it.next());
}
}
catch (NullPointerException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayList : [10, 20, 30, 40, 50]
Value is : 10
Value is : 20
Value is : 30
Value is : 40
Value is : 50
Example 2:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<String>
arrlist1 = new ArrayList<String>();
arrlist1.add( "A" );
arrlist1.add( "B" );
arrlist1.add( "C" );
arrlist1.add( "D" );
arrlist1.add( "E" );
System.out.println( "ArrayList : "
+ arrlist1);
Iterator it = arrlist1.iterator();
while (it.hasNext()) {
System.out.println( "Value is : "
+ it.next());
}
}
catch (NullPointerException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayList : [A, B, C, D, E]
Value is : A
Value is : B
Value is : C
Value is : D
Value is : E
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