AbstractList iterator() method in Java with Examples
The iterator() method of java.util.AbstractList class is used to return an iterator over the elements in this list in proper sequence.
This implementation returns a straightforward implementation of the iterator interface, relying on the backing list’s size(), get(int), and remove(int) methods.
Syntax:
public Iterator iterator()
Returns Value: This method returns an iterator over the elements in this list in proper sequence.
Below are the examples to illustrate the iterator() method.
Example 1:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<Integer>
arrlist1 = new ArrayList<Integer>();
arrlist1.add( 10 );
arrlist1.add( 20 );
arrlist1.add( 30 );
arrlist1.add( 40 );
arrlist1.add( 50 );
System.out.println( "ArrayList : "
+ arrlist1);
Iterator it = arrlist1.iterator();
while (it.hasNext()) {
System.out.println( "Value is : "
+ it.next());
}
}
catch (NullPointerException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayList : [10, 20, 30, 40, 50]
Value is : 10
Value is : 20
Value is : 30
Value is : 40
Value is : 50
Example 2:
import java.util.*;
public class GFG1 {
public static void main(String[] argv)
throws Exception
{
try {
AbstractList<String>
arrlist1 = new ArrayList<String>();
arrlist1.add( "A" );
arrlist1.add( "B" );
arrlist1.add( "C" );
arrlist1.add( "D" );
arrlist1.add( "E" );
System.out.println( "ArrayList : "
+ arrlist1);
Iterator it = arrlist1.iterator();
while (it.hasNext()) {
System.out.println( "Value is : "
+ it.next());
}
}
catch (NullPointerException e) {
System.out.println( "Exception thrown : " + e);
}
}
}
|
Output:
ArrayList : [A, B, C, D, E]
Value is : A
Value is : B
Value is : C
Value is : D
Value is : E
Last Updated :
26 Nov, 2018
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