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ABS() and AVG() function in SQLite

  • Last Updated : 08 Oct, 2021

1. ABS() Function :
ABS(X) is a math function used to get the absolute value of a number. 

Syntax –

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ABS(X)

The ABS(X) function takes a numeric argument X and returns its magnitude. 

SELECT ABS(-6);

Output –



6

If the argument X is a blob or string, the function gives 0.0 as the return value

SELECT ABS('gfg');

Output –

0.0

If the argument X is NULL the function returns NULL. 

SELECT ABS(NULL);

Output –

NULL

2. AVG() Function :
AVG(X) is an aggregate function used to calculate the average on a set of rows.

Syntax –

AVG(X)

The function yields a floating point value equal to the average of all NON-NULL values in the argument group X. 

SELECT AVG(1,2,3,4,5,6,7)

Output –



4.0

If there is a NULL value passed to the AVG() function, only  the non-NULL values are used in calculating the average.

SELECT AVG(10,20,30,NULL);

Output –

20.0

Strings and blobs present in the argument X are evaluated as 0. 

SELECT AVG(10,20,'word',30,);

Output –

20.0

The function returns a NULL if all the input values are NULL.

SELECT AVG(NULL,NULL,NULL);

Output –

NULL

Now, we are going to use a real database example. First, let’s create a table called students with columns name and age and insert some rows!

--create a table
CREATE TABLE students(
  id INTEGER PRIMARY KEY AUTOINCREMENT,
  name VARCHAR(255),
  age INT);

--insert multiple rows
INSERT INTO students(name,age) 
VALUES
    ('Mark',20),
    ('Mary',19),
    ('John',17),
    ('Lydia',25);

We’ll  then write a SELECT statement that gives us the average age for all the students using the AVG() function

SELECT AVG(age) FROM students;

Output –

20.25

Next, we will create a SELECT statement that returns the age difference between each student and a new student Tony who is aged 18 years.

SELECT 
    name,
    age,
    ABS(age-18) AS age_difference_against_Tony 
FROM students;

Output –

Output of a SELECT statement using ABS() function

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